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## A transformer connected to a 120 V (rms) ac line is to supply 13,000 V (rms) for a neon sign. To reduce shock hazard, a fuse is to be insert

Question

A transformer connected to a 120 V (rms) ac line is to supply 13,000 V (rms) for a neon sign. To reduce shock hazard, a fuse is to be inserted in the primary circuit; the fuse is to blow when the rms current in the secondary circuit exceeds 8.50 mA.

a. What is the ratio of secondary to primary turns of the transformer? b. What power must be supplied to the transformer when the rms secondary current is 8.50 mA?

c. What current rating should the fuse in the primary circuit have?

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Physics
5 months
2021-08-14T05:28:59+00:00
2021-08-14T05:28:59+00:00 2 Answers
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## Answers ( )

Answer:Explanation:Voltage in primary, Vp = 120 V

Voltage in secondary, Vs = 13000 V

Current in secondary, Is = 8.5 mA

(a)

Ns : Np = 108.33(b)

For an ideal transformer

Input power = Output power

Input Power = Vs x Is = 13000 x 0.0085

Input power = 110.5 Watt(c)

Ip = 920.8 mAAnswer with Explanation:We are given that

a.We know that

b

.c.