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## A trained stunt diver is diving off a platform that is 15 m high into a pool of water that is 45 cm deep. The height, h, in meters, of the s

Question

A trained stunt diver is diving off a platform that is 15 m high into a pool of water that is 45 cm deep. The height, h, in meters, of the stunt diver above the water, is modeled by h=-4.9t^2+12t+5, where t is the time in seconds after starting the dive.

a) How long is the stunt diver above 15 m?

b) How long is the stunt diver in the air?

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Mathematics
3 years
2021-08-12T18:47:16+00:00
2021-08-12T18:47:16+00:00 1 Answers
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## Answers ( )

Answer:a)0 seconds.b)The stunt diver is in the air for 2.81 seconds.Step-by-step explanation:Solving a quadratic equation:Given a second order polynomial expressed by the following equation:

.

This polynomial has roots such that , given by the following formulas:

Height of the diver after t seconds:a) How long is the stunt diver above 15 m?Quadratic equation with , so the parabola is concave down, and it will be above 15m between the two roots that we found for . So

Quadratic equation with . Then

Negative , which means that the stunt diver is never above 15m, so 0 seconds.

b) How long is the stunt diver in the air?We have to find how long it takes for the diver to hit the ground, that is, t for which . So

Quadratic equation with . Then

Time is a positive measure, so we take 2.81.

The stunt diver is in the air for 2.81 seconds.