A toy cart is pulled a distance of 6.00 m in a straight line across the floor. The force pulling the cart has a magnitude of 20.0 N and is d

Question

A toy cart is pulled a distance of 6.00 m in a straight line across the floor. The force pulling the cart has a magnitude of 20.0 N and is directed at 37° above the horizontal. What is the work done by this force?

in progress 0
Thạch Thảo 3 weeks 2021-08-22T18:34:44+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-22T18:36:30+00:00

    Given Information:  

    Horizontal distance = d = 6.0 m  

    Force = F = 20 N

    Angle = θ = 37°

    Required Information:  

    Work done = W = ?

    Answer:  

    Work done = 95.84 Joules

    Explanation:  

    The work done on toy cart is given by

    W = Fdcos(θ)

    Where F is the force applied, d is the distance by which the toy cart has been displaced, and θ is the angle between F and horizontal floor.  

    As you can see in the attached diagram, The force pulling the cart makes an angle of 37 with respect to the horizontal surface.

    W = 20*6*cos(37°)

    W = 95.84 Joules

    Therefore, 95.84 Joules of work has been by a force of 20 N to displace the toy cart by 6 meters.

    0
    2021-08-22T18:36:37+00:00

    Answer:

    W = 95.8J

    Explanation:

    Given

    S = 6.00m

    F =20.0N

    Theta = 37°

    W = FSCos(theta)

    W = 20×6.0×Cos(37)

    W = 95.8J

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )