A toy cannon launches a 46-g golf ball straight up into the air with a kinetic energy of 6.8 J. What must the ball’s velocity be

Question

A toy cannon launches a 46-g golf ball straight up into the air with a kinetic energy of 6.8 J. What must the

ball’s velocity be as it leaves the cannon?

A. 0.54 m/s

B. 0.79 m/s

C. 17 m/s

D. 80 m/s

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Huyền Thanh 2 months 2021-07-25T17:08:13+00:00 1 Answers 3 views 0

Answers ( )

    0
    2021-07-25T17:09:32+00:00

    Answer : The correct option is, (C) 17 m/s

    Explanation :

    Formula used :

    K.E=\frac{1}{2}mv^2

    where,

    K.E = kinetic energy = 6.8 J

    m = mass of object = 46 g = 0.046 kg    (1 kg = 1000 g)

    v = velocity

    Now put all the given values in the above formula, we get:

    K.E=\frac{1}{2}mv^2

    6.8J=\frac{1}{2}\times 0.046kg\times v^2

    6.8kg.m^2/s^2=\frac{1}{2}\times 0.046kg\times v^2

    v=17.19m/s\approx 17m/s

    Therefore, the ball’s velocity be as it leaves the cannon is, 17 m/s

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