A total charge of 9.0 mC passes through a cross-sectional area of a nichrome wire in 3.6s. The number of electrons passing through the cross

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A total charge of 9.0 mC passes through a cross-sectional area of a nichrome wire in 3.6s. The number of electrons passing through the cross-sectional area in 10s is

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  1. Given :

    • total charge = 9.0 mC = 0.009 C

    Each electron has a charge of :

    [tex]1.6 \times 10 {}^{ – 19} \: C[/tex]

    For producing 1 Cuolomb charge we need :

    • [tex] \mathrm{\dfrac{1}{1.6 \times 10 {}^{ – 19} } }[/tex]
    • [tex] \dfrac{10 {}^{19} }{1.6} [/tex]
    • [tex] \dfrac{10\times 10 {}^{19} }{16} [/tex]
    • [tex] \dfrac{100 \times 10 {}^{18} }{16} [/tex]
    • [tex] \mathrm{6.24 \times 10 {}^{18} \: \: electrons}[/tex]

    Now, for producing 0.009 C of charge, the number of electrons required is :

    • [tex]0.009 \times 6.24 \times {10}^{18} [/tex]
    • [tex]0.05616 \times 10 {}^{18} [/tex]
    • [tex] \mathrm{5.616 \times 10 {}^{16} \: \: electons}[/tex]

    _____________________________

    So, Number of electrons passing through the cross section in 3.6 seconds is :

    [tex] \mathrm{5.616 \times 10 {}^{16} \: \: electrons} [/tex]

    Number of electrons passing through it in 1 Second is :

    • [tex] \dfrac{5.616 \times {10}^{16} }{3.6} [/tex]
    • [tex] \mathrm{1.56 \times 10 {}^{16} \: \: electrons}[/tex]

    Now, in 10 seconds the number of electrons passing through it is :

    • [tex]10 \times \mathrm{1.56 \times 10 {}^{16} \: \: }[/tex]
    • [tex] \mathrm{1.56 \times 10 {}^{17} \: \: electrons}[/tex]

    _____________________________

    [tex]\mathrm{ \#TeeNForeveR}[/tex]

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