a torque of 6Nm is required to accelerate a wheel from rest to 7.5rev/s In a time of 5.0s.find the moment of inertia of the wheel​

Question

a torque of 6Nm is required to accelerate a wheel from rest to 7.5rev/s In a time of 5.0s.find the moment of inertia of the wheel​

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Sapo 4 years 2021-08-07T17:49:12+00:00 1 Answers 11 views 0

Answers ( )

  1. thachthao
    0
    2021-08-07T17:50:53+00:00
    Reply

    Your question has been heard loud and clear

    Torque = 6Nm

    Angular acceleration= 7.5 revolutions / second

    Moment of inertia = ?

     

    Torque = Moment of inertia * Angular acceleration

    Therefore , moment of intertia = Torque / Angular acceleration

    Moment of inertia = 6 / 7.5 = 0.8 Kgm^2

    Moment of inertia of wheel = 0.8 Kgm^2

    Thankyou

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