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## A tiger leaps with an initial velocity of 35.0 km/hr at an angle of 13.0ᶿ with respect to the horizontal. What are the components of the tig

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## Answers ( )

Answer:Vx = 35 x cos(13deg)

Vy = 35 x sin(13deg) – gt

(g is acceleration due to gravity =~9.8 meter/second^2, t is time in second)

Explanation:The tiger leaps up, then x and y component of its velocity are:

Vx = Vo x cos(alpha)

Vy = Vo x sin(alpha) – gt

(Vo is tiger’s initial velocity, alpha is angle between its leaping direction and horizontal plane)

Hope this helps!