A thin, circular disk of radius R = 30 cm is oriented in the yz-plane with its center as the origin. The disk carries a total charge Q = +3

Question

A thin, circular disk of radius R = 30 cm is oriented in the yz-plane with its center as the origin. The disk carries a total charge Q = +3 μC distributed uniformly over its surface. Calculate the magnitude of the electric field due to the disk at the point x = 15 cm along the x-axis.

in progress 0
Cherry 3 months 2021-07-19T16:10:30+00:00 1 Answers 107 views 0

Answers ( )

    0
    2021-07-19T16:11:49+00:00

    Answer:

    electric field due to the disk at the point x = 15 cm along the x-axis is;

    E = 3.31 x 10^(9) N/C

    Explanation:

    We are given;

    Radius;r = 30cm = 0.3m

    Charge; Q = +3 μC = +3 x 10^(-6) C

    Point, x = 15 cm = 0.15m

    The formula for electric field due to the disk on the x-axis is given by;

    E = [Q/(2ε₀•π•r²)] * [1 – (x/√(x² + r²))]

    Where;

    Q, x and r are as stated earlier

    ε₀ is the permittivity of free space and has a constant value of 8.85 x 10⁻¹² C²/N.m

    Thus, plugging in the relevant values, we have;

    E = [3 x 10^(-6)/(8.85 x 10⁻¹² x π x 0.3²)] * [1 – (0.15/√(0.15² + 0.3²))]

    E = 3.31 x 10^(9) N/C

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )