A thermometer reads a pressure of 120 kPa at 0 ˚C. What is the temperature when the thermometer reads a pressure of 80 kPa? (Celsius + 273 =

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A thermometer reads a pressure of 120 kPa at 0 ˚C. What is the temperature when the thermometer reads a pressure of 80 kPa? (Celsius + 273 = Kelvin) Use Gay Lussac’s Formula to solve. 182 K 192 K 202 K 212 K

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Nguyệt Ánh 1 year 2021-08-06T12:41:55+00:00 1 Answers 9 views 0

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    2021-08-06T12:43:10+00:00

    Answer:

    T₂ = 182 K

    Explanation:

    Given that,

    Initial pressure, P₁ = 120 kPa  

    Initial temperature, T₁ = 0˚C = 273 K

    We need to find the final temperature when the pressure is 80 kPa.

    We know that, Gay Lussac’s Formula is :

    [tex]\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}\\\\T_2=\dfrac{P_2T_1}{P_1}\\\\T_2=\dfrac{80\ kPa\times 273}{120\ kPa}\\\\T_2=182\ K[/tex]

    So, the new temperature is equal to 182 K.

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