A test taker gets 70 on 1st exam, 80 on 2nd exam, 2/3 of 4/5 of his 2nd exam on his 3rd test. If the professor gives 5 points extra credit o

Question

A test taker gets 70 on 1st exam, 80 on 2nd exam, 2/3 of 4/5 of his 2nd exam on his 3rd test. If the professor gives 5 points extra credit on his 4th exam and his average score is 80, what was his score on the 4th exam

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Gerda 3 years 2021-08-03T10:23:36+00:00 1 Answers 22 views 0

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  1. Sigrid
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    2021-08-03T10:24:48+00:00
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    Answer:  127

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    Explanation:

    The phrasing “2/3 of 4/5 of his 2nd exam on his 3rd test” is a bit clunky in my opinion. It seems more complicated than it has to be.

    The student got 80 on the second exam. 4/5 of this is (4/5)*80 = 0.8*80 = 64. Then we take 2/3 of this to get (2/3)*64 = 42.667 approximately. If we assume only whole number scores are given, then this would round to 43.

    Let x be the score on the fourth exam. Since 5 points of extra credit are given, the student actually got x+5 points on this exam.

    So we have these scores

    • first exam = 70
    • second exam = 80
    • third exam = 43
    • fourth exam = x+5

    Adding up these scores and dividing by 4 will get us the average

    (sum of scores)/(number of scores) = average

    (70+80+43+x+5)/4 = 80

    (x+198)/4 = 80

    x+198 = 4*80

    x+198 = 320

    x = 320 – 198

    x = 122

    So the student got a score of x+5 = 122+5 = 127 on the fourth exam.

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