A tennis ball of mass of 0.06 kg is initially traveling at an angle of 47o to the horizontal at a speed of 45 m/s. It then was shot by the t

Question

A tennis ball of mass of 0.06 kg is initially traveling at an angle of 47o to the horizontal at a speed of 45 m/s. It then was shot by the tennis player and return horizontally at a speed of 35 m/s. Find the impulse delivered to the ball.

in progress 0
Cherry 1 week 2021-07-20T11:04:35+00:00 1 Answers 6 views 0

Answers ( )

    0
    2021-07-20T11:06:18+00:00

    Answer:

    The impulse delivered to the ball is Imp = \left(-3.941, 1.975\right)\,\left[\frac{kg\cdot m}{s} \right].

    Explanation:

    By Impulse Theorem, the motion of the tennis ball is modelled after the following expression:

    Imp = m\cdot (\vec v_{f} - \vec v_{o}) (1)

    Where:

    m – Mass of the ball, in kilograms.

    \vec v_{o} – Vector of the initial velocity, in meters per second.

    \vec v_{f} – Vector of the final velocity, in meters per second.

    Imp – Impulse, in meters per second.

    If we know that m = 0.06\,kg, \vec v_{o} = \left(45\,\frac{m}{s} \right)\cdot (\cos 47^{\circ}, \sin 47^{\circ}) and \vec v_{f} = \left(35\,\frac{m}{s} \right)\cdot (-1, 0), then the impulse delivered to the ball is:

    Imp = (0.06\,kg)\cdot \left[\left(35\,\frac{m}{s} \right)\cdot (-1,0) -\left(45\,\frac{m}{s} \right)\cdot (\cos 47^{\circ}, \sin 47^{\circ})\right]

    Imp = (0.06\,kg)\cdot (-65.670, -32.911)\,\left[\frac{m}{s} \right]

    Imp = \left(-3.941, 1.975\right)\,\left[\frac{kg\cdot m}{s} \right]

    The impulse delivered to the ball is Imp = \left(-3.941, 1.975\right)\,\left[\frac{kg\cdot m}{s} \right].

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )