A technical machinist is asked to build a cubical steel tank that will hold 410 L of water. Calculate in meters the smallest possible inside

Question

A technical machinist is asked to build a cubical steel tank that will hold 410 L of water. Calculate in meters the smallest possible inside length of the tank. Round your answer to the nearest .001 .

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Gia Bảo 3 years 2021-08-15T04:20:29+00:00 1 Answers 28 views 0

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    2021-08-15T04:21:41+00:00

    Answer:

    0.743 m

    Step-by-step explanation:

    Given that :

    Volume of cubical tank = 410 L

    Volume of a cube = L³

    First we convert 410 L into meter cube

    1 L = 10^-3 m³

    1L = 0.001 m³

    410 L = (410 * 0.001) m³

    410 L = 0.410 m³

    0.410 = l^3

    Cube root of both sides

    (0.410)^1/3 = l

    0.7428958 = l

    l = 0.7428958 m

    Hence, smallest possible inside length of the cube would be : 0.743m

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