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A technical machinist is asked to build a cubical steel tank that will hold 410 L of water. Calculate in meters the smallest possible inside
Question
A technical machinist is asked to build a cubical steel tank that will hold 410 L of water. Calculate in meters the smallest possible inside length of the tank. Round your answer to the nearest .001 .
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Mathematics
3 years
2021-08-15T04:20:29+00:00
2021-08-15T04:20:29+00:00 1 Answers
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Answer:
0.743 m
Step-by-step explanation:
Given that :
Volume of cubical tank = 410 L
Volume of a cube = L³
First we convert 410 L into meter cube
1 L = 10^-3 m³
1L = 0.001 m³
410 L = (410 * 0.001) m³
410 L = 0.410 m³
0.410 = l^3
Cube root of both sides
(0.410)^1/3 = l
0.7428958 = l
l = 0.7428958 m
Hence, smallest possible inside length of the cube would be : 0.743m