A supertanker filled with oil has a total mass of 6.1 x108 kg. If the dimensions of the ship are those of a rectangular box 300 meters long,

Question

A supertanker filled with oil has a total mass of 6.1 x108 kg. If the dimensions of the ship are those of a rectangular box 300 meters long, 80 meters wide, and 40 meters high, determine how far the bottom of the ship is below sea level. 4. [psea 1 020 kgm3 =
a) 10 m
b) 15 m
c) 20 m
d) 25 m
e) 30 m

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Yến Oanh 2 months 2021-07-21T12:27:59+00:00 1 Answers 2 views 0

Answers ( )

    0
    2021-07-21T12:29:34+00:00

    Answer:

    The bottom of the sea is 25 m below sea level.

    Explanation:

    Given data

    Mass = 6.1 × 10^{8} \ kg

    \rho_{sea} = 1020\  \frac{kg}{m^{3} }

    We know that Buoyant force on the tank is equal to gravity force of the tank.

    F_B = F_g

    (\rho_{Fluid}) (g) (V_{disp}) = m g

    (\rho_{Fluid})  (V_{disp}) = m

    1020 × V_{disp} = 6.1 × 10^{8}

    V_{disp} = 598039.21 m^{3}

    We know that

    V_{disp} = W × L × H

    598039.21 = 300 × 80 × H

    H = 25 m

    Therefore the bottom of the sea is 25 m below sea level.

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