A student solving for the acceleration of an object has applied appropriate physics principles and obtained the expression a = a1 + Fm where

Question

A student solving for the acceleration of an object has applied appropriate physics principles and obtained the expression a = a1 + Fm where a1 = 3.00 m/s2, F = 12.0 kg.m/s2 and m = 7.00 kg. First, which of the following is the correct step for obtaining a common denominator for the two fractions in the expression in solving for a?
a. (m/m times a1/1) + (1/1 times F/m).
b. (1/m times a1/1) + (1/m times F/m).
c. (m/m times a1/1) + (F/F times F/m).
d. (m/m times a1/1) +(m/m times F/m ).

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Ngọc Khuê 3 months 2021-07-19T16:32:47+00:00 1 Answers 132 views 0

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    2021-07-19T16:33:56+00:00

    Answer:

    A. \ a = (\frac{m}{m}\times \frac{a_1}{1})  + (\frac{1}{1}\times \frac{F}{m})

    Explanation:

    Given the expression for calculating the acceleration as shown;

    a = a_1 + \frac{F}{m} where;

    a_1 = 3.00m/s^2\\\\F = 12.0kg.m/s^2\\\\m = 7.00kg\\

    To get the correct step for obtaining a common denominator for the two fractions in the expression in solving for a, we will find the LCM of  the given expression as shown;

    a = a_1 + \frac{F}{m}\\\\a = \frac{a_1}{1}+\frac{F}{m}\\  \\a = \frac{(m*a_1)+F}{m} \\\\a = \frac{ma_1+F}{m}\\ \\a = (\frac{m}{m}\times \frac{a_1}{1})  + (\frac{1}{1}\times \frac{F}{m})

    The final expression gives the requires step. On substituting the given parameters into the resulting expression to get a;

    a = (\frac{7}{7}\times \frac{3}{1})  + (\frac{1}{1}\times \frac{12}{7})\\\\a = \frac{21}{7} + \frac{12}{7}\\  \\a = \frac{21+12}{7}\\ \\a = \frac{33}{7} m/s^2

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