## A student solving for the acceleration of an object has applied appropriate physics principles and obtained the expression a = a₁ + Fm where

Question

A student solving for the acceleration of an object has applied appropriate physics principles and obtained the expression a = a₁ + Fm where a₁ = 3.00 meter/second², F = 12.0 kilogram⋅meter/second² and m =7.00 kilogram. First, which of the following is the correct step for obtaining a common denominator for the two fractions in the expression in solving for a?
a. (m/m times a₁/1) + (1/1 times F/m)
b. (1/m times a₁/1) + (1/m times F/m)
c. (m/m times a₁/1) + (F/F times F/m)
d. (m/m times a₁/1) +(m/m times F/m )

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1 week 2021-07-22T09:49:45+00:00 1 Answers 1 views 0

The correct option is option (a).

The acceleration of an object is m/s².

Explanation:

Given expression is [ divide a whole number by 1 to turn into a fraction. Since is a whole number, so is divided by 1 to turn into a fraction] [The l.c.m of the denominators 1 and m is m. Now multiply both numerator and denominator by m of and multiply both numerator and denominator by 1 of ] The correct option is option (a)

Given that,

F= 12.0 kg.m/s² , m=7.00 kg and = 3.00 m/s²     m/s²

The acceleration of an object is m/s².