A student slides her 80.0-kg desk across the level floor of her dormitory room a distance 4.40 m at constant speed. If the coefficient of ki

Question

A student slides her 80.0-kg desk across the level floor of her dormitory room a distance 4.40 m at constant speed. If the coefficient of kinetic friction between the desk and the floor is 0.400, how much work did she do

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Thiên Di 5 months 2021-08-18T14:51:45+00:00 1 Answers 0 views 0

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    2021-08-18T14:53:28+00:00

    Answer:

    F = umg where u is coefficient of dynamic friction

    Explanation:

    F = 0.4 x 80 x 9.81 = 313.92 N

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