a student drops a ball off the top of building and records that the ball takes 3.32s to reach the ground (g=9.8 m/s^2). what is the ball’s s

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a student drops a ball off the top of building and records that the ball takes 3.32s to reach the ground (g=9.8 m/s^2). what is the ball’s speed just before hitting the ground?​

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Thiên Ân 2 weeks 2021-07-22T06:31:39+00:00 1 Answers 1 views 0

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    2021-07-22T06:33:15+00:00

    Answer:

    Explanation:

    Use the one-dimensional equation for motion

    v = v₀ + at and filling in,

    v = 0 + (-9.8)(3.32) so

    v = -33 m/s (negative because it is going downwards and upwards is positive).

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