A student drops a ball off the top of building and records that the ball takes 3.32s to reach the ground (g = 9.8 m/s^2). What is the ball s

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A student drops a ball off the top of building and records that the ball takes 3.32s to reach the ground (g = 9.8 m/s^2). What is the ball speed just before hitting the ground?​

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MichaelMet 1 day 2021-07-22T06:45:55+00:00 1 Answers 0 views 0

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    2021-07-22T06:47:15+00:00

    Answer:

    Explanation:

    Here’s what we know because it was given to us:

    a = -9.8 m/s/s and

    time = 3.32 seconds

    Here’s what we know because we rock physics:

    v₀ = 0 (because the object was held still before it was dropped).

    Here’s the equation that ties all that info together in a single one-dimensional equation:

    v = v₀ + at

    Filling in and solving for v:

    v = 0 + (-9.8)(3.32) and

    v = -33m/s

    The velocity is negative because the object is moving downwards and up is positive (but you knew that already too!)

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