A string of length 2.00 m is stretched between two fixed points with enough tension to make the transverse wave speed 40.0 m/s on the string

Question

A string of length 2.00 m is stretched between two fixed points with enough tension to make the transverse wave speed 40.0 m/s on the string. What are the wavelength and frequency of:

a. the fundamental mode of the standing wave.
b. 1st overtone
c. The 3rd harmonic

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Thu Hương 22 hours 2021-07-21T18:54:59+00:00 1 Answers 0 views 0

Answers ( )

    0
    2021-07-21T18:56:51+00:00

    Answer:

    Explanation:

    The fundamental mode of the standing wave in string is expressed as;

    fo

    F = V/2L where;

    V is the speed of the transverse wave

    L is the length of the string

    Given

    V = 40.0m/s

    L = 2.00m

    F = 40.0/2(2)

    F = 40/4

    F = 10Hertz

    Hence the fundamental mode of the standing wave is 10Hz

    Overtone/harmonics are integral multiples of the fundamental frequency.

    Note that 1st overtone is also called second harmonic

    Second harmonic  

    First overtone F1 = 2F

    Second overtone/Third harmonics = 3F

    First overtone F1 = 2*10

    First overtone = 20Hz

    3rd harmonic = 3*10

    3rd harmonic = 30Hz

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