A string is attached to a vibrating machine that has a frequency of 120 Hz. The other end of the string is passed over a pulley of negligibl

Question

A string is attached to a vibrating machine that has a frequency of 120 Hz. The other end of the string is passed over a pulley of negligible mass and friction and is attached to a weight hanger which holds a mass m=0.5kg. What is the tension in newtons?

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Thiên Thanh 6 months 2021-07-22T15:08:28+00:00 1 Answers 15 views 0

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    2021-07-22T15:09:37+00:00

    Answer:

    Explanation:

    Given that,

    The frequency of vibration is 120Hz

    The mass of object attached is 0.5kg.

    We want to find the tension In the string

    The tension in the string is the weight of the object, it is how much gravity is pulling the object to the centre of the earth

    Using newton second law.

    F_net = m•a_y

    The body is not accelerating the y-direction, then, a_y = 0

    F_net = 0

    Force acting on the string is the weight of the object and the tension in the string

    T – W = 0

    T = W

    Where weight is mass × gravity

    W = mg

    Then,

    T = W = mg

    T = mg = 0.5 × 9.81

    T = 4.905 N

    The tension in the string is 4.905 N

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