A stretched spring has an elastic potential energy of 35 J when it is stretched 0.54 m. What is the spring constant of the spring? Round you

Question

A stretched spring has an elastic potential energy of 35 J when it is stretched 0.54 m. What is the spring constant of the spring? Round your answer to two significant figures.

StartFraction N over m EndFraction

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King 4 years 2021-07-13T10:18:20+00:00 1 Answers 66 views 0

Answers ( )

  1. kiet
    0
    2021-07-13T10:19:44+00:00
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    Answer:

    240 N/m

    Explanation:

    Using the formula as follows:

    U = ½kx²

    Where;

    U = elastic potential energy (J)

    K = spring constant (N/m)

    x = stretched displacement (m)

    According to the information provided in this question,

    U = 35J

    x = 0.54m

    k = ?

    U = ½kx²

    35 = ½ × k × 0.54²

    35 = ½ × k × 0.2916

    35 = 0.2916k/2

    70 = 0.2916k

    k = 70 ÷ 0.2916

    k = 240.05

    To 2s.f, the spring constant (k) = 240 N/m.

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