A straight wire is positioned in a uniform magnetic field so that the maximum force on it is 4.0 N. If the wire is 80 cm long and carries a

Question

A straight wire is positioned in a uniform magnetic field so that the maximum force on it is 4.0 N. If the wire is 80 cm long and carries a current that is 2 A, what is the magnitude of the magnetic field

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Huyền Thanh 4 years 2021-08-18T23:41:40+00:00 1 Answers 17 views 0

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    2021-08-18T23:42:51+00:00

    Answer:

    B = 2.5 T

    Explanation:

    F = 4 N

    l = 80cm = 0.8 m

    I = 2 A

    B = ?

    at maximum titha = 90degree

    F = BILsin(thita)

    sin90 = 1

    F = BIL

    ==> B = F/IL

    B= 4 ÷ (2×0.8)

    B= 4 ÷ 1.6

    B= 2.5 T

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