A stone was dropped off a cliff and hit the ground with a speed of 136 ft/s. What is the height of the cliff

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A stone was dropped off a cliff and hit the ground with a speed of 136 ft/s. What is the height of the cliff

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Huyền Thanh 4 years 2021-07-17T19:27:08+00:00 1 Answers 22 views 0

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  1. RobertKer
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    2021-07-17T19:29:00+00:00
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    Answer:

    Explanation:

    Use the equation

    v^2=v_0^2+2aΔx

    In this dimension (the y dimension…the only one we have to care about for this problem), here’s what we know:

    a = -32 ft/s/s

    v₀ = 0 m/s (since someone was holding the stone still before it was dropped)

    v = 136 ft/s

    Δx = ??

    Filling in:

    136^2=0^2+2(-32)Δx so

    Δx = \frac{136^2}{2(-32)} so

    Δx = -289 feet (negative because the stone dropped that many feet below the point from which it was dropped, but you would answer a height question with the positive of this number. If you were asked how far the stone dropped, it would be negative; if you’re asked how tall the cliff is, that would be positive)

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