A stone is thrown with an initial upward velocity of 7.0 m/s and experiences negligible air resistance. If we take upward as the positive di

Question

A stone is thrown with an initial upward velocity of 7.0 m/s and experiences negligible air resistance. If we take upward as the positive direction, what is the velocity of the stone after 0.50 s?

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3 years 2021-07-31T20:12:28+00:00 1 Answers 225 views 0

2.1 m/s

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 7 m/s

Time (t) = 0.50 s

Final velocity (v) =?

Since the is thrown upward, it means that the stone is going against gravity. Thus, the value of the acceleration due to gravity will be negative i.e – 9.8 m/s²

Thus, we can obtain the velocity of the stone after 0.50 s as follow:

Initial velocity (u) = 7 m/s

Time (t) = 0.50 s

Acceleration due to gravity (g) = – 9.8 m/s²

Final velocity (v) =?

v = u + gt

v = 7 + (– 9.8 × 0.5)

v = 7 – 4.9

v = 2.1 m/s

Therefore the velocity of the stone after 0.5 s is 2.1 m/s.