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A stone is dropped into a deep well and is heard to hit the water 3.41 s after being dropped. Determine the depth of the well.
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Answers ( )
Answer:
57.0 m
Explanation:
Assume the time it takes for the sound to reach the top of the well is negligible.
Given:
v₀ = 0 m/s
a = 9.8 m/s²
t = 3.41 s
Find: Δy
Δy = v₀ t + ½ at²
Δy = (0 m/s) (3.41 s) + ½ (9.8 m/s²) (3.41 s)²
Δy = 57.0 m