A stone falls freely from rest for 8.0 s. a. Calculate the stone’s velocity after 8.0 s. b. What is the stone’s displacement dur

Question

A stone falls freely from rest for 8.0 s.
a. Calculate the stone’s velocity after 8.0 s.
b. What is the stone’s displacement during
this time?

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Bình An 2 months 2021-07-20T10:31:12+00:00 1 Answers 5 views 0

Answers ( )

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    2021-07-20T10:32:59+00:00

    a) The acceleration that the stone has is the gravitational acceleration and it is always the same (Actually not but assumed to be so)

    The gravitational acceleration is 9.81 m/s²

    Since this acceleration is always constant, we can use the formula of V = g × t, where V is velocity, g is the gravitational acceleration and t is time.

    Let’s use this formula: V = g × t = 9.81 × 8.0 = 78.48 m/s

    b) Displacement in free falls is calculated by the formula of d = 1/2 × g × t², which is actually derivated from average velocity.

    If we use the formula, d = 1/2 × 9.81 × 8² = is found to be 313.92 m

    If there is anything you do not understand or anything is wrong, please let me know and I am sorry for my bad English ^^

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