A steel wire of length 1.5 m and diameter 1 mm is joined to an aluminum wire of identical dimensions to make a composite wire of length 3 m.

Question

A steel wire of length 1.5 m and diameter 1 mm is joined to an aluminum wire of identical dimensions to make a composite wire of length 3 m. Find the resulting change in the length of this composite wire if an object with a mass of 5 kg is hung vertically from one of its ends. (Neglect any effects the masses of the two wires have on the changes in their lengths.). Use 2 x 1011 N/m2 and 0.7 x 1011 N/m2 for the Young’s modulus for steel and aluminum respectively.

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Jezebel 1 week 2021-07-21T23:56:44+00:00 1 Answers 4 views 0

Answers ( )

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    2021-07-21T23:58:26+00:00

    Answer:

    1.805 mm

    Explanation:

    Extension in the steel wire = WL_{steel}/AE_{steel}

    Extension in the aluminium wire = WL_{Al}/AE_{Al}

    Total extension = W/A * (L_{steel}/E_{steel} + L_{Al}/E_{Al})

    we have:

    W = mg

    W = 5 × 9.8

    W = 49 N

    Area A = π/4 × (0.001)²

    = 7.85398 × 10 ⁻⁷ m²

    Total extension = W/A * (L_{steel}/E_{steel} + L_{Al}/E_{Al})

    Total extension = 49/ 7.85398 × 10 ⁻⁷ ( (1.5/ 200×10⁹) + 1.5/ 70×10⁹))

    Total extension =  0.0018048

    Total extension = 1.805 mm

    Thus, the total extension = the resulting change in the length of this composite wire = 1.805 mm

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