A steady stream of projectiles, with identical linear momenta, collides with a fixed target. The average force on the target is proportional

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A steady stream of projectiles, with identical linear momenta, collides with a fixed target. The average force on the target is proportional to *

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6 months 2021-07-16T16:09:37+00:00 1 Answers 14 views 0

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    2021-07-16T16:11:20+00:00

    Answer:

    The average force on the target is proportional to:

    – The number of projectiles hitting the target.

    – The mass of the projectiles.

    – If the time increases or decreases

    Explanation:

    This is a problem that applies momentum and the amount of movement. Where this principle can be explained by the following equation:

    m*v1 + Imp1_2 = m*v2

    where:

    ∑F *Δt = Imp1_2 = impulse. [N*s]

    m*v1  = mass by velocity before the impact [kg*m/s]

    m*v2  = mass by velocity after the impact [kg*m/s]

    When a problem includes two or more particles, each particle it can be considered separately and equation is written for every particle.

    We clear the expression of force in the equation:

    ∑F *Δt  = m*v2 – m*v1

    In this equation if we have a different number of particles, given by the value n, we see that the equation is proportional to the number of particles

    ∑F *Δt  = n*m*v2 – n*m*v1

    Therefore the average force on the target is proportional to the number of projectiles hitting the target.

    The Force F is also increased or decreased if the mass of the projectiles is changed. Therefore it is also proportional to the mass of the projectiles.

    The Force F also changes if the time increases or decreases.

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