A square current loop 5.20 cm on each side carries a 460 mA current. The loop is in a 0.900 T uniform magnetic field. The axis of the loop,

Question

A square current loop 5.20 cm on each side carries a 460 mA current. The loop is in a 0.900 T uniform magnetic field. The axis of the loop, perpendicular to the plane of the loop, is 30° away from the field direction.
What is the magnitude of the torque on the current loop?

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Yến Oanh 8 months 2021-07-17T07:32:50+00:00 1 Answers 6 views 0

Answers ( )

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    2021-07-17T07:34:00+00:00

    The magnitude of the torque on the current loop is 0.0055 Nm

    Explanation:

    Given data,

    We  have the formula,

    T= u x B

    Where u=  i x A

    T= i×A×B ×sin(30)

    T=0.46×0.52² ×0.900×0.5

    T=0.0055 Nm

    The magnitude of the torque on the current loop is 0.0055 Nm

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