A spring with k = 83 N????m hangs vertically next to a ruler. The end of the spring is next to the 15-cm mark on the ruler. If a 2.5-kg mass

Question

A spring with k = 83 N????m hangs vertically next to a ruler. The end of the spring is next to the 15-cm mark on the ruler. If a 2.5-kg mass is now attached to the end of the spring, and the mass is allowed to fall, where will the end of the spring line up with the ruler marks when the mass is at its lowest position?

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Doris 5 months 2021-08-29T20:45:39+00:00 1 Answers 19 views 0

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    2021-08-29T20:47:13+00:00

    Answer:

    0.4452m

    Explanation:

    Spring constant is given as:

    k=F/x

    But F is mass times velocity(gravitational acceleration(=9.8m/s^2)

    83N/m=2.5kg([tex]9.8m/s^2)/x[/tex]

    x=0.2952m

    Therefore the ruler reading will be x+0.15m. Hence the ruler reading is 0.4451m

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