A spring that obeys Hooke’s law has a spring force constant of 266 N/m. This spring is then stretched by 28.4 cm. (a) What is the magnitude

Question

A spring that obeys Hooke’s law has a spring force constant of 266 N/m. This spring is then stretched by 28.4 cm. (a) What is the magnitude of the force required to stretch the spring by this distance

in progress 0
Ngọc Khuê 2 months 2021-07-23T04:52:10+00:00 1 Answers 2 views 0

Answers ( )

    0
    2021-07-23T04:53:54+00:00

    Answer:

    75.544 N.

    Explanation:

    From Hooke’s law,

    Applying,

    F = ke………………………… Equation 1

    Where F = Force required to stretch the spring, k = force constant of the spring, e = extension.

    From the question,

    Given: k = 266 N/m, e = 28.4 cm = 0.284 m

    Substitute these values into equation 1

    F = 266(0.284)

    F = 75.544 N.

    Hence the force required to stretch the spring is 75.544 N

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )