## A spring stretches by 0.0173 m when a 2.62-kg object is suspended from its end. How much mass should be attached to this spring so that its

Question

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## Answers ( )

Answer

4.16kg mass should be added

Explanation:

Step one :

Given

Extention e=0.0173m

Suspended Mass m=2.62kg

Frequency f=3hz

But F=ma

F=2.62*9.81

F=25.6N

Step two

Applying the hooks law equation

F=ke

Where k is the spring constant

k=F/e

k=25.6/0.0173

k=1480N/m

Step three

To solve for the additional mass that causes a frequency of vibration of 3hz

m=k/4*pi²*f²

Substituting our values into the equation we have

m=1480/4*3.142²*3²

m=1480/355.4

m=4.16kg