a spring of spring constant k=12.5N/m is hung vertically. a 0.500kg mass is then suspended from the spring. what is the displacement of the

Question

a spring of spring constant k=12.5N/m is hung vertically. a 0.500kg mass is then suspended from the spring. what is the displacement of the end of the spring due to the wieght of the 0.500 kg mass?

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Diễm Kiều 5 months 2021-08-18T01:32:50+00:00 1 Answers 39 views 0

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    2021-08-18T01:34:27+00:00

    Answer:

    The displacement of one end of the spring due to weight = 0.4 m.

    Explanation:

    Given :

    Spring constant (k) = 12.5 \frac{N}{m}

    Mass (m) = 0.5 kg

    From the hooke’s law,

    Force is proportional to the negative of the displacement.

      F -x

      F = -kx

    Where minus sign represent that, the force is always directed toward mean position.

    Now one force is gravity mg acts as a downward. so we write,

      mg = kx

    Here we take only magnitude.

        x = \frac{mg}{k}

    Where x = displacement of one end of spring, g = 10 \frac{m}{s^{2} }

        x = \frac{0.5\times 10}{12.5}

        x = 0.4 m

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