A spring is hung vertically with a 425g mass attached to it. The mass is at rest. If the mass causes the spring to stretch 0.67 m, what is t

Question

A spring is hung vertically with a 425g mass attached to it. The mass is at rest. If the mass causes the spring to stretch 0.67 m, what is the spring constant?

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Mộc Miên 4 years 2021-08-04T02:26:04+00:00 1 Answers 11 views 0

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  1. Amity
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    2021-08-04T02:27:58+00:00
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    Answer:

    6.22 N/m

    Explanation:

    F=xk  Making k the subject of the formula then

    k=\frac {F}{x}

    But since the applied force F is mg then we substitute mg with F is the formula hence

    k=\frac {mg}{x}

    Converting the given mass from g to Kg, we divide it by 1000 hence m= 0.425 and taking g as 9.81 and substituting x with 0.67 m then

    k=\frac {0.425\times 9.81}{0.67 m}=6.222761194\ N/m\approx 6.22\ N/m

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