A speed skater moving to the left across frictionless ice at 8.0 m/s hits a 5.0-m-wide patch of rough ice. She slows steadily, then continue

Question

A speed skater moving to the left across frictionless ice at 8.0 m/s hits a 5.0-m-wide patch of rough ice. She slows steadily, then continues on at 6.0 m/s. What is her acceleration on the rough ice?

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Mộc Miên 2 months 2021-07-29T10:40:33+00:00 1 Answers 9 views 0

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    2021-07-29T10:42:07+00:00

    Answer:

    Acceleration, a=-2.8\ m/s^2

    Explanation:

    It is given that,

    The initial speed of a speed skater, u = 8 m/s

    The final speed of a speed skater, v = 6 m/s

    Width of patch of rough ice, s = 5 m

    We need to find the acceleration on the rough ice. Acceleration can be calculated using third equation of motion as :

    v^2-u^2=2as\\\\a=\dfrac{v^2-u^2}{2s}\\\\a=\dfrac{(6)^2-(8)^2}{2\times 5}\\\\a=-2.8\ m/s^2

    So, the acceleration on the rough ice is 2.8\ m/s^2. Negative sign shows that its speed is decreased.

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