A solid cube of material is 1.50 cm on the edge. It submerged totally in oil of ρ = 820 kg/m3 .Find the buoyancy force of the material.​

Question

A solid cube of material is 1.50 cm on the edge. It submerged totally in oil of ρ = 820 kg/m3 .Find the buoyancy force of the material.​

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Vodka 2 months 2021-08-02T07:53:53+00:00 1 Answers 2 views 0

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    2021-08-02T07:55:09+00:00

    Answer:

    0.027 N

    Explanation:

    From the question,

    According to Archimedes principle,

    The buoyancy force on the material = weight of oil displaced by the solid cube = Upthrust on the solid cube.

    Applying,

    U =ρ×V×g……………. Equation 1

    Where U = Upthrust on the solid cube, ρ = density of oil, V = Volume of the solid cube, g = acceleration due to gravity

    But,

    V = l³……………. Equation 2

    Substitute equation 2 into equation 1

    U = gρl³………….. Equation 3

    Given: ρ = 820 kg/m³, l = 1.50 cm = 0.015 m

    Constant: g = 9.8 m/s²

    Substitute these values into equation 3

    U = 820×0.015³×9.8

    U = 0.027 N

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