A solenoid of length 10 cm has 247 turns and a magnetic field at the center of 1.2 T. What is the current through the solenoid?

Question

A solenoid of length 10 cm has 247 turns and a magnetic field at the center of 1.2 T. What is the current through the solenoid?

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Mít Mít 12 hours 2021-07-21T20:41:42+00:00 1 Answers 0 views 0

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    2021-07-21T20:42:55+00:00

    Answer:

    386.6 A

    Explanation:

    We are given;

    Solenoid length; L = 10 cm = 0.1 m

    Number of turns; N = 247

    Magnetic field; B = 1.2 T

    Now, at the centre of a long solenoid of N turns/metre carrying a current(I), the formula for the magnetic field is given as;

    B = μ_oNI/L

    Making I the subject we have;

    I = BL/μ_oN

    Where μ_o is the vacuum of permeability and has a constant value of 4π × 10^(−7) H/m

    Thus;

    I = (1.2 × 0.1)/(4π × 10^(−7) × 247)

    I = 386.6 A

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