A soft drink (mostly water) flows in a pipe at a beverage plant with a mass flow rate that would fill 220 0.355 – L cans per minute. At poin

Question

A soft drink (mostly water) flows in a pipe at a beverage plant with a mass flow rate that would fill 220 0.355 – L cans per minute. At point 2 in the pipe, the gauge pressure is 152kPa and the cross-sectional area is 8.00cm2. At point 1, 1.35m above point 2, the cross-sectional area is 2.00cm2.

Part a

Find the mass flow rate. kg/s

part b

Find the volume flow rate. L/s

part c

Find the flow speed at point 1. m/s

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Linh Đan 3 months 2021-07-19T16:21:39+00:00 1 Answers 7 views 0

Answers ( )

    0
    2021-07-19T16:22:40+00:00

    Answer:

    a) 1.3 kg/s

    b) 0.0013 m³/s

    c) 3.25 m/s

    Explanation:

    Given

    Mass flow rate = (220 * 0.355) / 60

    Mass flow rate = 78.1 / 60

    Mass flow rate = 1.3 kg/s

    Volume flow rate =

    Recall, Density = mass / volume, so

    Volume = mass / density, where

    Density of water = 1000 kg/m³

    Volume flow rate = mass flow rate / density

    Volume flow rate = 1.3 / 1000

    Volume flow rate = 0.0013 m³/s

    Flow speed at point 1

    V = volume flow rate / area

    Area at point 1 = 2 cm² = 0.0004 m²

    Flow speed at point 1 is

    V = 0.0013 / 0.0004

    V = 3.25 m/s

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