A soccer player kicks a ball with initial velocity of 10m/s at an angle of 30 degrees above the horizontal-.what is the magnitude of the

Question

A soccer player kicks a ball with initial velocity of 10m/s at an angle of 30 degrees above the horizontal…..what is the magnitude of the vector

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Thạch Thảo 4 years 2021-08-28T16:31:47+00:00 1 Answers 133 views 0

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  1. Nho
    0
    2021-08-28T16:33:05+00:00
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    Answer: 10m/s^2

    Explanation:

    Given the following :

    Initial Velocity(U) = 10m/s

    Angle of inclination = 30°

    In other to calculate the magnitude of the vector,

    We need to resolve into verti AL and horizontal component.

    Vertical component of a vector(Uy) = U × Sinθ

    Horizontal component(Ux) = U × Cosθ

    Uy = 10 × sin30 = 10 × 0.5 = 5m/s

    Ux = 10 × Cos30 = 10 × 0.866 = 8.66m/s

    Therefore the magnitude equals :

    U = √(Uy)^2 + (Ux)^2

    U = √5^2 + 8.66^2

    U = √25 + 74.9956

    U = √99.9956

    U = 9.9997799

    U = 10m/s^2

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