A soap bubble of radius R is situated in a uniform electric field of magnitude E. The electric flux through the surface of the soap bubble i

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A soap bubble of radius R is situated in a uniform electric field of magnitude E. The electric flux through the surface of the soap bubble is

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Hồng Cúc 6 months 2021-08-15T03:37:34+00:00 1 Answers 15 views 0

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    2021-08-15T03:38:46+00:00

    Answer:

    The electric flux around the soap bubble will be

    Ф = q/ε

    Explanation:

    The radius of the soap bubble = R

    The electric field around the soap bubble = E

    The electric flux = ?

    The soap can be approximated to be a sphere, so we find the surface area of the sphere

    For the soap bubble, the surface area will be

    A =  4\pi R^{2}

    Recall that electric flux is given as

    Ф = EA

    substituting value of A from above, we’ll have

    Ф = E4\pi R^{2}….. equ 1

    Also recall that the electric field E is given as

    E = q/(4πεR^{2})

    substitute the value of E into equ 1, to get

    Ф = q/(4πεR^{2}) * 4\pi R^{2}

    The electric flux around the soap bubble reduces to

    Ф = q/ε

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