. A small car of mass m and a large car of mass 2m drive around a highway curve of radius R. Both cars travel at the same speed (v). The

Question

. A small car of mass m and a large car of mass 2m drive around a highway curve of radius R. Both cars travel at the same speed (v). The
centripetal acceleration (Grad) of the large car is the centripetal acceleration of the small car.
four times
twice
half
equal to

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Linh Đan 2 months 2021-07-29T20:04:38+00:00 1 Answers 0 views 0

Answers ( )

    0
    2021-07-29T20:05:39+00:00

    Complete question is;

    A small car of mass m and a large car of mass 2m drive around a highway curve of radius R. Both cars travel at the same speed (v). The

    centripetal acceleration (Grad) of the large car is the centripetal acceleration of the small car. How does the Force of the small car FS compare to the force of the large car FL as they round the curve.

    four times

    twice

    half

    equal to

    Answer:

    Half

    Explanation:

    Formula for centripetal force is given as;

    F = mv²/R

    Where;

    v is velocity

    R is radius

    Now, centripetal acceleration is given by;

    a = v²/R

    Since they both travel with the same velocity V and radius remains the same, we can say that;

    F = ma

    For the small car;

    FS = ma

    For the big car;

    FL = 2ma

    This means the force of the small car is half of that of the Large car

    Thus;

    FS = ½FL

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