A skydiver of mass m jumps from a hot air balloon and falls a distance d before reaching a terminal velocity of magnitude v . Assume that th

Question

A skydiver of mass m jumps from a hot air balloon and falls a distance d before reaching a terminal velocity of magnitude v . Assume that the magnitude of the acceleration due to gravity is g .

-What is the work (Wd) done on the skydiver, over the distance , by the drag force of the air?

-Find the power (P d) supplied by the drag force after the skydiver has reached terminal velocity v.

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Mít Mít 4 years 2021-08-14T22:25:41+00:00 1 Answers 121 views 0

Answers ( )

  1. thienan
    0
    2021-08-14T22:26:58+00:00
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    Answer:

    a. Wd = ½mv²−mgd

    b. Pd = -mgv

    Explanation:

    The skydiver losses potential energy and gains kinetic energy.

    Work done by gravity

    W=mg

    Therefore, work done by gravity is given as

    P.E= weight × height

    P.E= mg × d

    P.E= mgd

    The work done by kinetic energy

    K.E=½mv²

    Then, the drag work becomes

    We=K.E-P.E

    We=½mv² – mgd

    b. Drag power

    Power is given as

    Power=force × velocity

    The force =weight =mg

    g is negative since or is against gravity (upward motion)

    Pd=F×v

    Pd=-mgv

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