A single-turn circular loop of wire of radius 45 mm lies in a plane perpendicular to a spatially uniform magnetic field. During a 0.10 s tim

Question

A single-turn circular loop of wire of radius 45 mm lies in a plane perpendicular to a spatially uniform magnetic field. During a 0.10 s time interval, the magnitude of the field increases uniformly from 250 to 350 mT. (a) Determine the emf induced in the loop (in V). (Enter the magnitude.) V (b) If the magnetic field is directed out of the page, what is the direction of the current induced in the loop

in progress 0
Thiên Thanh 2 weeks 2021-07-20T04:29:48+00:00 1 Answers 4 views 0

Answers ( )

    0
    2021-07-20T04:31:42+00:00

    Answer:

    Magnitude of induced emf is 0.00635 V

    Explanation:

    Radius of circular loop r = 45 mm = 0.045 m

    Area of circular loop A=\pi r^2

    A=3.14\times 0.045^2=0.00635m^2

    Magnetic field is increases from 250 mT to 350 mT

    Therefore change in magnetic field dB=250-350=100mT

    Emf induced is given by

    e=-N\frac{d\Phi }{dt}=-NA\frac{dB}{dt}

    e=-0.00635\times \frac{100\times 10^{-3}}{0.10}=-0.00635V

    Magnitude of induced emf is equal to 0.00635 V

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )