A simple pendulum with a length of 2 m oscillates on the Earth’s surface. What is the period of oscillations?

Question

A simple pendulum with a length of 2 m oscillates on the Earth’s surface. What is the period of oscillations?

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Dulcie 5 months 2021-08-22T14:17:48+00:00 1 Answers 7 views 0

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    2021-08-22T14:19:08+00:00

    Answer:

    Period, T = 27.84 seconds

    Explanation:

    Given the following data;

    Length of pendulum = 2m

    We know that acceleration due to gravity on earth is equal to 9.8 m/s²

    To find the period of oscillation of the simple pendulum;

    Mathematically, it is given by the formula;

     Period, T = 2 \pi \sqrt {lg}

    Substituting into the equation, we have;

     Period, T = 2 * 3.142 * \sqrt {2*9.8}

     Period, T = 6.284 * \sqrt {19.6}

     Period, T = 6.284 * 4.43

    Period, T = 27.84 seconds

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