A simple generator is used to generate a peak output voltage of 25.0 V . The square armature consists of windings that are 7.0 cm on a side

Question

A simple generator is used to generate a peak output voltage of 25.0 V . The square armature consists of windings that are 7.0 cm on a side and rotates in a field of 0.490 T at a rate of 60.0 rev/s . Part A How many loops of wire should be wound on the square armature

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Thu Thảo 3 years 2021-08-16T03:51:55+00:00 1 Answers 77 views 0

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  1. haidang
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    2021-08-16T03:53:31+00:00
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    Answer:

    The 28 loops wound on the square armature

    Explanation:

    Peak output voltage \epsilon _{peak} = 25 V

    Area of square armature A = (7 \times 10^{-2} )^{2} = 49 \times 10^{-4}

    Magnetic field B = 0.490 T

    Angular frequency \omega = 2\pi f = 2 \pi \times 60 = 120\pi

    According to the law of electromagnetic induction,

         \epsilon _{peak} = NBA \omega

    Where N = number of loops of wire.

      N = \frac{25}{49 \times 10^{-4} \times 0.49 \times 120\pi }

      N = 27.6 ≅ 28

    Thus, 28 loops of wire should be wound on the square armature.

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