A sealed metal can was left in a storage room. the pressure inside the can was 1.0 atm at a temperature of 27 “C. A fire in the room heated

Question

A sealed metal can was left in a storage room. the pressure inside the can was 1.0 atm at a temperature of 27 “C. A fire in the room heated the can to a point at which the pressure reached 2.5 atm and the can exploded. What was the approximate temperature inside the can Just before it exploded?​

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Xavia 4 years 2021-08-04T20:20:34+00:00 1 Answers 17 views 0

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  1. Jezebel
    0
    2021-08-04T20:21:50+00:00
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    Answer:

    477 °C

    Explanation:

    Step 1: Given data

    • Initial pressure (P₁): 1.0 atm
    • Initial temperature (T₁): 27 °C
    • Final pressure (P₂): 2.5 atm

    Step 2: Convert 27 °C to Kelvin

    We will use the following expression.

    K = °C + 273.15 = 27 + 273.15 = 300 K

    Step 3: Calculate the final temperature (T₂)

    If we assume constant volume (before the can explodes) and ideal behavior, we can calculate the final temperature using Gay-Lussac’s law.

    T₁/P₁ = T₂/P₂

    T₂ = T₁ × P₂/P₁

    T₂ = 300 K × 2.5 atm/1.0 atm = 750 K

    In Celsius,

    °C = K – 273.15 = 750 – 273.15 = 477 °C

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