A sample of nitrogen gas in a 750.0 mL sealed flask exerts a pressure of 206.58 kPa. Calculate the temperature of the gas if the flask conta

Question

A sample of nitrogen gas in a 750.0 mL sealed flask exerts a pressure of 206.58 kPa. Calculate the temperature of the gas if the flask contains 3.00 grams of gas.

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Hồng Cúc 5 months 2021-08-11T10:15:08+00:00 1 Answers 20 views 0

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    2021-08-11T10:16:46+00:00

    Answer:

    T= -99 °C.

    Explanation:

    Hello there!

    In this case, according to the given description of the problem, it is possible for us to analyze this problem via the ideal gas equation:

    PV=nRT

    However, we first calculate the moles in 3.00 grams of nitrogen gas (28.01 g/mol):

    n=3.00g*\frac{1mol}{28.01g}=0.107mol

    Next, we solve for the temperature as shown below:

    T=\frac{PV}{Rn}

    Next, we convert the given pressure and volume to atm and L to obtain:

    T=\frac{(206.58atm/101.325)*750.0L/1000}{0.08206\frac{atm*L}{mol*K}*0.107mol}\\\\T=174.15K-273.15\\\\T=-99\°C

    Regards!

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