A sample of Kr gas is observed to effuse through a porous barrier in 3.79 minutes. Under the same conditions, the same number of moles of an

Question

A sample of Kr gas is observed to effuse through a porous barrier in 3.79 minutes. Under the same conditions, the same number of moles of an unknown gas requires 2.66 minutes to effuse through the same barrier. The molar mass of the unknown gas is________ g/mol.

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Vodka 4 years 2021-07-25T10:53:44+00:00 1 Answers 7 views 0

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  1. kiet
    0
    2021-07-25T10:54:56+00:00
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    Answer:

    M'=41.3g/mol

    Explanation:

    From the question we are told that:

    Time Through first barrier T_1=3.79min

    Time Through second barrier T_2=2.66min

    Generally the Grahams Law equation for   time of diffusion is mathematically given by

     T=K\sqrt{M}

    Where

    M=Mass Number of Kr

     M=83.8

    Therefore

     {T}{\sqrt{M}={T}{\sqrt{M'}

     {3.79}{\sqrt{83.8}={2.66}{\sqrt{M'}

     M'=0.645

     M'=41.3g/mol

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