A sample of chlorine gas occupies a volume of 0.025L at 300 K. At 600K, what will the volume be? A)808 L B)50 L C)0.050 L

Question

A sample of chlorine gas occupies a volume of 0.025L at 300 K. At 600K, what will the volume be?
A)808 L
B)50 L
C)0.050 L
D)0.088 L

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Maris 5 months 2021-08-16T04:47:30+00:00 1 Answers 2 views 0

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    0
    2021-08-16T04:48:33+00:00

    Answer:  The volume at 600 K will be 0.050 L.

    Explanation:

    Given: V_{1} = 0.025 L,    T_{1} = 300 K

    V_{2} = ?,             T_{2} = 600 K

    Formula used is as follows.

    \frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}

    Substitute the values into above formula as follows.

    \frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{0.025 L}{300 K} = \frac{V_{2}}{600 K}\\V_{2} = 0.050 L

    Thus, we can conclude that the volume at 600 K will be 0.050 L.

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