A sample of bromine gas at 79.06 kPa experiences a change in volume from 63.299 L to 69.057 L. What is the resulting pressure in kilop

Question

A sample of bromine gas at 79.06 kPa experiences a change in volume from 63.299 L to 69.057 L.
What is the resulting pressure in kilopascals? Pressure 1 x volume 1=pressure 2 x volume 2

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Eirian 4 years 2021-07-24T22:19:39+00:00 1 Answers 5 views 0

Answers ( )

  1. Orla
    0
    2021-07-24T22:20:58+00:00
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    Answer:

    74.47 kPa

    Explanation:

    As provided in the question, Boyle’s law follows that

    Pressure 1 x volume 1=pressure 2 x volume 2

    Given that

    Pressure 1 =79.06 kPa

    volume 1=63.299L

    pressure 2=unknown

    Volume 2=69.057L

    Substituting these into the formula then

    79.06*63.299=69.057*P2

    Making pressure 2 the subject of the formula

    P_2=\frac {79.06*63.299}{69.057}=72.467945899763\\P_2\approx 74.47kPa

    Therefore, the resulting pressure, rounded off to two decimal places is approximately 74.47 kPa

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